Answer
$a = 3.13\times 10^3~m/s^2$
Work Step by Step
In part (c), we found that the force on the sphere is $F = 1.66\times 10^{-11}~N$
We can find the magnitude of the acceleration of the sphere:
$F = ma$
$a = \frac{F}{m}$
$a = \frac{F}{V~\rho}$
$a = \frac{F}{\frac{4}{3}\pi~r^3~\rho}$
$a = \frac{(3)(1.66\times 10^{-11}~N)}{(4\pi)~(633\times 10^{-9}~m)^3~(5000~kg/m^3)}$
$a = 3.13\times 10^3~m/s^2$
