Answer
$p_r = 4.7\times 10^{-6}~Pa$
Work Step by Step
We can use Equation (33-34) to find the radiation pressure:
$p_r = \frac{I}{c}$
$p_r = \frac{1400~W/m^2}{3.0\times 10^8~m/s}$
$p_r = 4.7\times 10^{-6}~Pa$
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