Answer
$p_{r}=4.0 \times 10^{-7} \mathrm{~Pa} $
Work Step by Step
The radiation pressure is
$$
p_r=\frac{d p / d t}{A}=\frac{8.0 \times 10^{-7} \mathrm{~N}}{2.0 \mathrm{~m}^2}\\=4.0 \times 10^{-7} \mathrm{~Pa} .
$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 33 - Electromagnetic Waves - Problems - Page 1002: 27h
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