Answer
1.33 A
Work Step by Step
Encircled displacement current $i_{d,enc}=\frac{encircled\,area}{full\,plate\,area}\times i_{d}$
$=\frac{\pi (R/3)^{2}}{\pi R^{2}}\times i_{d}=\frac{i_{d}}{9}=\frac{12.0\,A}{9}=1.33\,A$
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