Answer
$\oint_{\vec{B}} \cdot d \vec{s}=6.3×10−7 T⋅m.$
Work Step by Step
(d) The integral of the field around the indicated path is
$$
\oint_{\vec{B}} \cdot d \vec{s}=\mu_0 i_d^{\prime}=\left\{1.26 \times 10^{-16} \mathrm{H} / \mathrm{m}|| 0.50 \mathrm{~A}\right\}\\=6.3 \times 10^{-7} \mathrm{~T} \cdot \mathrm{m} .
$$
