Answer
$i_d^{\prime}=0.50$
Work Step by Step
The displacement current through the indicated path is
$$
i_d^{\prime}=i_d\left(\frac{d^2}{L^2}\right)=(2.0 \mathrm{~A})\left(\frac{0.50 \mathrm{~m}}{1.0 \mathrm{~m}}\right)^2\\=0.50 \mathrm{~A} .
$$