Answer
We can rank the circuits according to the current amplitude:
$(3) \gt (1) \gt (2)$
Work Step by Step
We can write a general equation for the charge:
$q = Q~cos~\omega t$
The current amplitude is $~~I = \omega Q$
We can find the current amplitude for each circuit:
Circuit (1):
$Q = 2$
$\omega = 4$
$I = \omega Q = (4)(2)= 8$
Circuit (2):
$Q = 4$
$\omega = 1$
$I = \omega Q = (1)(4)= 4$
Circuit (3):
$Q = 3$
$\omega = 4$
$I = \omega Q = (4)(3)= 12$
We can rank the circuits according to the current amplitude:
$(3) \gt (1) \gt (2)$
