Answer
The angular frequency $\omega_d$ of the emf is less than the natural angular frequency $\omega$
Work Step by Step
The current reaches a maximum value slightly before the emf reaches a maximum value.
Therefore, the current leads the emf.
When the current leads the emf, then $X_C \gt X_L$
In this case, the circuit is said to be more capacitive than inductive.
That is, the circuit's load is mainly capacitive.
To reach a state of resonance in this case, we would need to increase $\omega_d$ in order to decrease $X_C$ and increase $X_L$ which would result in resonance when $\omega_d = \omega$
At present, the angular frequency $\omega_d$ of the emf is less than the natural angular frequency $\omega$
