Answer
$B=0.00570 T$
Work Step by Step
To find the magnetic field inside the solenoid, use the formula that the magnetic field inside the solenoid equals $$B=\mu_o ni$$ where $n$ is the number of turns per unit length. Find the number of turns to get an $n$ value of $$n=\frac{N}{L}=\frac{1200turns}{95.0cm}=12.6turns/cm$$ Substituting known values of $\mu_o=4\pi \times 10^{-7} H/m$, $n=12.6turns/cm=1260turns/m$, and $i=3.60A$ yields a magnetic field of $$B=(4\pi \times 10^{-7} H/m)(1260 turns/m)(3.60A)=0.00570 T$$
