Answer
$B = 4.00\times 10^{-4}~T$
Work Step by Step
We can find the magnetic field at the outer radius:
$B = \frac{\mu_0~i~N}{2\pi~r}$
$B = \frac{(4\pi\times 10^{-7}~H/m)~(0.800~A)(500)}{(2\pi)~(0.200~m)}$
$B = 4.00\times 10^{-4}~T$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 29 - Magnetic Fields Due to Currents - Problems - Page 861: 49b
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