Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 29 - Magnetic Fields Due to Currents - Problems - Page 860: 45b

Answer

$\int~B\cdot ds = 0$

Work Step by Step

We can find $\int~B\cdot ds$: $\int~B\cdot ds = \mu_0~i_{enc}$ $\int~B\cdot ds = (4\pi\times 10^{-7}~H/m)(2.0~A+2.0~A-2.0~A-2.0~A)$ $\int~B\cdot ds = (4\pi\times 10^{-7}~H/m)(0)$ $\int~B\cdot ds = 0$
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