Answer
The potential difference across the resistor is $~~1.0~V$
Work Step by Step
We can find the potential difference across the resistor:
$P = \frac{V^2}{R}$
$V^2 = P~R$
$V = \sqrt{P~R}$
$V = \sqrt{(10~W)(0.10~\Omega)}$
$V = 1.0~V$
The potential difference across the resistor is $~~1.0~V$
