Answer
We can rank the wires according to the magnitude of the electric field halfway to the surface:
$a \gt b \gt c$
Work Step by Step
We can consider the equation: $~~E = \rho~J$
Since the wires are made from the same material, then $\rho$ is equal for all three wires.
Therefore, the magnitude of the electric field is greater when the current density $J$ is greater.
At $r = \frac{R}{2}$, wire a has the greatest current density $J$, while wire c has the smallest current density.
We can rank the wires according to the magnitude of the electric field halfway to the surface:
$a \gt b \gt c$
