## Fundamentals of Physics Extended (10th Edition)

$120\ V$
The voltage across $C_2$ can be found using the formula: $V_2 =\frac{q_2}{C_2}$ As capacitor are arranged in series, $q_1 =q_2 =480\ \mu C$ Thus: $V_2 =\frac{480\ \mu C}{4\ \mu F}$ $V_2 =120\ V$