Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 744: 67a

Answer

$2.4\ \mu F$

Work Step by Step

Given: $C_1 = 6\ \mu F$ $C_2 = 4\ \mu F$ Potential difference $\Delta V = 200 V$ When two capacitance's $C_1$ and $C_2$ are connected in series their equivalent capacitance is $\frac{1}{C_{equ}} = \frac{1}{C_1}+\frac{1}{C_2}$ $\frac{1}{C_{equ}} = \frac{1}{6\ \mu F}+\frac{1}{4\ \mu F} $ $\frac{1}{C_{equ}} =0.4166\ \mu F$ $C_{equ} = 2.4\ \mu F$
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