Answer
$80\ V$
Work Step by Step
The potential difference across $C_1 $ is $V_1 =\frac{q_1}{C_1}$
We know that:
$q_1 =480\mu C$ (from 67-b)
$C_1 = 6\mu F$
Therefore;
$V_1 =\frac{480\ \mu C}{6\ \mu F}$
$V_1 = 80\ V$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 744: 67c
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