Answer
$E_{net} \neq 0$
Work Step by Step
We can write a general equation for the net electric potential:
$V_{net} = \frac{1}{4\pi~\epsilon_0}\sum \frac{q_i}{r_i}$
We can write a general equation for the net electric field:
$E_{net} = \frac{1}{4\pi~\epsilon_0}\sum \frac{q_i}{r_i^2}$
Let's assume that $~~V_{net} = 0$
Then $~~\frac{q_1}{r_1} = -\frac{q_2}{r_2}$
Since $~~q_1 \neq -q_2$, we know that $~~r_1 \neq r_2$
Then $~~\frac{q_1}{r_1^2} \neq -\frac{q_2}{r_2^2}$
Then $~~E_{net} \neq 0$
