Answer
Point B should be at a higher electric potential.
Work Step by Step
We can use Equation (24-9) to write an expression for the change in kinetic energy:
$\Delta K = -q~\Delta V = -q~(V_B-V_A)$
An electron has a negative charge.
In order for $\Delta K$ to be positive, then $(V_B-V_A)$ must be positive.
Then $~~V_B \gt V_A$
Point B should be at a higher electric potential.
