## Fundamentals of Physics Extended (10th Edition)

$v=1.48\times 10^7\frac{m}{s}$
According to law of conservation of energy; $K.E=\Delta U$ $\implies \frac{1}{2}mv^2=q\Delta V$ This simplifies to $v=\sqrt{\frac{2q \Delta V}{m}}$ We plug in the known values to obtain: $v=\sqrt{\frac{2(1.6\times 10^{-19})(625)}{9.109\times 10^{-31}}}=1.48\times 10^7\frac{m}{s}$