Answer
$U=0.484$ MeV
Work Step by Step
We know that;
$U=\frac{K(\frac{2e}{3})^2}{r}$
We plug in the known values to obtain:
$U=\frac{9\times 10^9\times (\frac{2(1.6\times 10^{-19})}{3})^2}{1.32\times 10^{-15}}$
$U=7.7575\times 10^{-14}J$
$U=7.7575\times 10^{-14}J\times (\frac{1eV}{1.6\times 10^{-19}})$
$U=0.484\times 10^6eV$
$U==0.484M eV$
