Answer
$V = \frac{Q}{4\pi~\epsilon_0~r}$
Work Step by Step
Note that all the charge is inside a sphere of radius $r$ since $r \gt r_2$
We can find the electric potential:
$V = \frac{Q}{4\pi~\epsilon_0~r}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 24 - Electric Potential - Problems - Page 716: 95a
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