Answer
$E=15.0\frac{N}{C}$
Work Step by Step
We know that:
$E=\frac{1}{4\pi \epsilon_{\circ}}\frac{q}{r^2}$
We plug in the known values to obtain:
$E=8.99\times 10^9\times \frac{6.00\times 10^{-12}}{(0.0600)^2}=15.0\frac{N}{C}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 23 - Gauss' Law - Problems - Page 684: 78a
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