Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 684: 70b

Answer

$E=2.4\times 10^3\frac{N}{C}$

Work Step by Step

We know that: $E=\frac{1}{4\pi \epsilon_{\circ}}\frac{q}{r^2}$ We plug in the known values to obtain: $E=8.99\times 10^9\times \frac{1.68\times 10^{-9}}{0.8^2}$ $E=2.4\times 10^3\frac{N}{C}$
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