Answer
$E=2.4\times 10^3\frac{N}{C}$
Work Step by Step
We know that:
$E=\frac{1}{4\pi \epsilon_{\circ}}\frac{q}{r^2}$
We plug in the known values to obtain:
$E=8.99\times 10^9\times \frac{1.68\times 10^{-9}}{0.8^2}$
$E=2.4\times 10^3\frac{N}{C}$