Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 684: 75

Answer

$q=3.6\times 10^{-9}C$

Work Step by Step

As we know that; $\phi=EA$ $\implies \phi=E2\pi RL$ (where $A=2\pi RL)$ According to Gauss's law $\phi=\frac{q}{\epsilon_{\circ}}$ This can be rearranged as: $q=\epsilon_{\circ}\phi$ $\implies q=\epsilon_{\circ}E2\pi RL$ We plug in the known values to obtain: $q=8.85\times 10^{-12}(2.9\times 10^4)(2\times 3.1416)(0.014)(0.16)=3.6\times 10^{-9}C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.