Answer
$E = 60~N/C$
Work Step by Step
We can find the magnitude of the electric field:
$E = \frac{q}{4\pi~\epsilon_0~r^2}$
$E = \frac{6.0\times 10^{-6}~C}{(4\pi)~(8.854\times 10^{-12}~F/m)~(30~m)^2}$
$E = 60~N/C$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 23 - Gauss' Law - Problems - Page 681: 37b
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