Answer
$E=2.4\times 10^2\frac{N}{C}$
Work Step by Step
We know that:
$E=\frac{2\lambda}{4\pi \epsilon_{\circ}r}$
We plug in the known values to obtain:
$E=\frac{2(2.0\times 10^{-9})}{4(3.1416)(8.85\times 10^{-12})(0.15)}=2.4\times 10^2\frac{N}{C}$
