Answer
5 seconds
Work Step by Step
The car has a constant deceleration of 4.92 $m/s^2$, meaning that a = -4.92 $m/s^2$. The initial velocity is 24.6m/s and we are interested in how long it takes to come to a stop (v = 0). Therefore we use:
$v = v0 + at$ and solve for t
$0 = 24.6m/s + (-4.92m/s^2)t $
and we find that t = 5 seconds
