Answer
17.6 m/s
Work Step by Step
We know the electron has an acceleration of 3.2 $m/s^2 $ and that its velocity at this point in time is 9.6m/s. We call this time t = 0. We are interested in the velocity 2.5 seconds later, or t = 2.5
We use the equation
$ v = v0 + at = 9.6m/s + (3.2m/s^2)(2.5s) = 17.6 m/s$
