Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 541: 15

Answer

360.5$^{\circ}$C or 733.7 K

Work Step by Step

Given/Needed from charts: Rod is steel, ring is brass. I will represent them with s for steel and b for brass Ts = 25.00$^{\circ}$C Ls = 3.000 cm Tb = 25.00$^{\circ}$C Lb = 2.992 cm $\alpha$b = 19 * $10^{-6}$ $\frac{1}{{\circ}C}$ $\alpha$s = 11 * $10^{-6}$ $\frac{1}{{\circ}C}$ We will need this equation: $\Delta$L = Lf - Li = L$\alpha$$\Delta$T Also stated as Lf = L$\alpha$$\Delta$T + Li For the ring to fit, the Tf of the brass ring must equal the Tf of the steel rod. Thus, Ls$\alpha$s$\Delta$T + Lis = Lb$\alpha$b$\Delta$T + Lib Plug in: (3)(11 * $10^{-6}$)$\Delta$T + 3 = (2.992) (19 * $10^{-6}$)$\Delta$T+2.992 Simplifying: (33 * $10^{-6}$)$\Delta$T + 0.008 = (56.848 * $10^{-6}$)$\Delta$T Bring $\Delta$T to one side and factor out the coefficients: $\Delta$T*(56.848 * $10^{-6}$ - 33 * $10^{-6}$) = 0.008 Thus: $\Delta$T = $\frac{0.008}{(56.848 * 10^{-6} -33 * 10^{-6})}$ = 335.5$^{\circ}$C This is a change in temperature, so you can represent it as either Kelvin or Celsius. Since they are asking for the final temperature, not the change in temperature: Ts + $\Delta$T = 360.5$^{\circ}$C Or, converting to SI units: 360.5$^{\circ}$C + 373.2$^{\circ}$C = 733.7 K
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