Answer
1.366
Work Step by Step
Recall: $T=(273.16\,K)(\underset{gas\to0}{\lim}\frac{p}{p_{3}})$
$T\rightarrow$ temperature in kelvins
$p\rightarrow$ pressure of the gas at measured temperature
$p_{3}\rightarrow$ pressure of the gas at 273.16 K
Given: T= 373.15 K
Result: $(\underset{gas\to0}{\lim}\frac{p}{p_{3}})=\frac{T}{273.16\,K}=\frac{373.15\,K}{273.16\,K}=1.366$
