Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 541: 9

Answer

2.731 cm

Work Step by Step

$D_{new}=D+\Delta D$ As the equation for linear thermal expansion is applicable to diameters, $\Delta D=D\alpha\Delta T$ Therefore, we can write $D_{new}=D+D\alpha\Delta T=D(1+\alpha \Delta T)$ Given: $D=2.725\,cm$, $\Delta T=100.0^{\circ}C$, Coefficient of linear expansion of Al=$23\times10^{-6}/C^{\circ}$ Result: $D_{new}=2.725\,cm(1+23\times10^{-6}/C^{\circ}\times100.0^{\circ}C)$ $=2.731\,cm$
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