Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 409: 40

Answer

$6.5\;mm$

Work Step by Step

According to Archimedes’ principle the buoyant force is equal to the alligator’s weight $F_b=W\;........................(1)$ or, $\rho_w gAh=mg$ or, $\rho_w Ah=m$ Let, the alligator would sink additional $\Delta h$ after swallowing stones Now, the Eq. $(1)$ becomes, $\rho_w g A(h+\Delta h)=(m+\Delta m)g$ or, $\rho_w A\Delta h=\Delta m$ or, $\Delta h=\frac{\Delta m}{\rho_w A}$ Substituting the given values $\Delta h=\frac{0.01\times130}{1000\times0.20}$ or, $\Delta h=6.5\times10^{-3}\;m$ or, $\boxed{\Delta h=6.5\;mm}$
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