Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 382: 58b

Answer

The orbital radius is $~~0.0096~r_E$

Work Step by Step

We can find the orbital radius: $T = \frac{2\pi~r}{v}$ $r = \frac{v~T}{2\pi}$ $r = \frac{(70~m/s)~(1500\times 24\times 3600~s)}{2\pi}$ $r = 1.44\times 10^9~m$ We can express the orbital radius in terms of the Earth's orbital radius: $\frac{r}{r_E} = \frac{1.44\times 10^9~m}{1.50\times 10^{11}~m}$ $\frac{r}{r_E} = 0.0096$ $r = 0.0096~r_E$ The orbital radius is $~~0.0096~r_E$
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