Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 382: 47

Answer

We can estimate that there are $~~5.07\times 10^{10}~~$ stars in the galaxy.

Work Step by Step

We can express the period in units of seconds: $T = (2.5\times 10^8)(365)(24)(3600~s)$ $T = 7.884\times 10^{15}~s$ We can use Kepler's Third Law to find the total mass $M$ of all the stars: $T^2 = (\frac{4\pi^2}{GM})~r^3$ $M = \frac{4\pi^2~r^3}{GT^2}$ $M = \frac{(4\pi^2)~(2.2\times 10^{20}~m)^3}{(6.67\times 10^{-11}~N~m^2/kg^2) (7.884\times 10^{15}~s)^2}$ $M = 1.014\times 10^{41}~kg$ We can find the number of stars: $\frac{1.014\times 10^{41}~kg}{2.0\times 10^{30}~kg} = 5.07\times 10^{10}$ We can estimate that there are $~~5.07\times 10^{10}~~$ stars in the galaxy.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.