Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 382: 48

Answer

Approximately 1.87 years. The value given in Appendix C is 1.88 years.

Work Step by Step

Let the distance between earth and sun's center be $R_{E}$. Then, Mars-sun distance = 1.52$\times R_{E}$ Time period of earth = 1 year We use Kepler's third law to obtain Time period of Mars in years. If $T_{M}$ is the Time period of Mars, then $\frac{(T_{M})^{2}}{1 year}$= $\frac{(1.52\times R_{E})^{3}}{(R_{E})^{3}}$ Or $T_{M}= (1.52)^{3/2} \times 1 year$ = 1.87 years.
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