Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 379: 4

Answer

$\frac{F_{Sun}}{F_{Earth}} = 2.2$

Work Step by Step

We can write an expression for $F_{Sun}$: $F_{Sun} = \frac{G~M_S~M_M}{d_S^2}$ We can write an expression for $F_{Earth}$: $F_{Earth} = \frac{G~M_E~M_M}{d_E^2}$ We can find $\frac{F_{Sun}}{F_{Earth}}$: $\frac{F_{Sun}}{F_{Earth}} = \frac{\frac{G~M_S~M_M}{d_S^2}}{\frac{G~M_E~M_M}{d_E^2}}$ $\frac{F_{Sun}}{F_{Earth}} = \frac{M_S~d_E^2}{M_E~d_S^2}$ $\frac{F_{Sun}}{F_{Earth}} = \frac{(2.0\times 10^{30}~kg)~(3.82\times 10^8~m)^2}{(5.98\times 10^{24}~kg)~(1.5\times 10^{11}~m)^2}$ $\frac{F_{Sun}}{F_{Earth}} = 2.2$
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