Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems: 3


$F$ = $\frac{GMm}{r^2}$ ${F}{r ^2}$ = ${GMm}$ $r ^2$ = $\frac{GMm}F$ $\sqrt{r ^2}$=${\sqrt\frac{GMm}F}$ $r$ = ${\sqrt\frac{6.67\times{10 ^{-11}} \times 5.5 \times 2.4}{2.3\times 10 ^{-12}}}$ $r$ = $19.02 m$

Work Step by Step

1. According to Newton's Law of universal Gravitation $F$ = $\frac{GMm}{r^2}$ 2. We have to find separation that is 'r' between the particles. 3. After shifting '${r ^ 2}$' to left side of equation, we take square root on both sides and then put the values to get the value of 'r' which is 19.02m or after rounded it off you can say 19.0 m
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.