Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 379: 11b

Answer

The net gravitational force on the central sphere is zero.

Work Step by Step

In part (a), we found that $M = m$ We can let the mass of the central sphere be $2~m_4$ By symmetry, the horizontal component of the net gravitational force on the central sphere is zero. Let the distance from the central sphere to the other spheres be $d$ We can find the vertical component of the net gravitational force on the central sphere: $F_y = \frac{G~M~(2~m_4)}{d^2} - 2 \times\frac{G~m~(2~m_4)}{d^2}~sin~30^{\circ}$ $F_y = \frac{G~M~(2~m_4)}{d^2} - \frac{G~m~(2~m_4)}{d^2}$ $F_y = \frac{G~m~(2~m_4)}{d^2} - \frac{G~m~(2~m_4)}{d^2}$ $F_y = 0$ The net gravitational force on the central sphere is zero.
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