Answer
The tension in the cable is $~~88~N$
Work Step by Step
To find the tension $F_T$ in the cable, we can consider the net torque about a rotation axis at the hinge:
$\sum \tau = 0$
$h~F_T~cos~\theta-L~F = 0$
$h~F_T~cos~\theta = L~F$
$F_T = \frac{L~F}{h~cos~\theta}$
$F_T = \frac{(3.2~m)(50~N)}{(2.0~m)~cos~25^{\circ}}$
$F_T = 88~N$
The tension in the cable is $~~88~N$
