Answer
The tension in cable A is $~~8010~N$
Work Step by Step
The tension in cable A is equal in magnitude to the weight of the bucket:
$T_A = mg$
$T_A = (817~kg)(9.8~m/s^2)$
$T_A = 8010~N$
The tension in cable A is $~~8010~N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 12 - Equilibrium and Elasticity - Problems - Page 351: 59a
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