Answer
If a frictionless block were to slide down the incline at that angle, its acceleration magnitude would be more than $0.10~g$
An opposing force of static friction directed up the incline causes the magnitude of the acceleration of the sphere's center of mass to be less than the magnitude of the acceleration down a frictionless incline.
Work Step by Step
If a frictionless block were to slide down the incline at that angle, its acceleration magnitude would be more than $0.10~g$
Since the ball rolls down the incline instead of sliding, there must be a force of static friction directed up the incline that gives the sphere an angular acceleration. This opposing force of static friction causes the magnitude of the acceleration of the sphere's center of mass to be less than the magnitude of the acceleration down a frictionless incline.