Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 320: 1i

Answer

$v = 0$

Work Step by Step

We can convert the speed of the car to units of $m/s$: $v = (80~km/h)\times (\frac{1000~m}{1~km})\times (\frac{1~h}{3600~s}) = 22~m/s$ The velocity of the tire's center of mass is equal to the velocity of the car. We can find the velocity of the bottom of the tire: $v = v_{com}-v_{com} = (22~m/s)-(22~m/s) = 0$ Since the hitchhiker's velocity is $0$, the velocity of the bottom of the tire relative to the hitchhiker is $(0-0)$ which is $0$ We can express this velocity in unit-vector notation: $v = 0$
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