Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems: 80

Answer

Please see the work below.

Work Step by Step

We know that $Nsin{\theta}=\frac{mv^2}{r}$............eq(1) and $Ncos{\theta}$=mg...........eq(2) Dividing eq(1) by eq(2), we obtain: $tan{\theta}=\frac{v^2}{rg}$ This can be rearranged as: $\frac{v^2}{r}=gtan{\theta}$ $\implies a=gtan{\theta}$ We plug in the known values to obtain: $a=(10)(\frac{1}{2})$ $a=5\frac{m}{s^2}$
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