Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems: 74

Answer

Please see the work below.

Work Step by Step

We know that according to given scenario $Tcos{\theta}=\frac{mv^2}{r}$...........eq(1) and $Tsin{\theta}=mg$..............eq(2) dividing eq(1) by eq(2), we obtain: $cot{\theta}=\frac{v^2}{rg}$ This can be rearranged as: $v^2=rgcot{\theta}$ $\implies v=\sqrt{rgcot{\theta}}$ We plug in the known values to obtain: $v=8.2\frac{m}{s}$ Thus, it is not moving faster than the bullet.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.