Essential University Physics: Volume 1 (3rd Edition)

We know that according to given scenario $Tcos{\theta}=\frac{mv^2}{r}$...........eq(1) and $Tsin{\theta}=mg$..............eq(2) dividing eq(1) by eq(2), we obtain: $cot{\theta}=\frac{v^2}{rg}$ This can be rearranged as: $v^2=rgcot{\theta}$ $\implies v=\sqrt{rgcot{\theta}}$ We plug in the known values to obtain: $v=8.2\frac{m}{s}$ Thus, it is not moving faster than the bullet.