## Essential University Physics: Volume 1 (3rd Edition)

We know that the balloon falls 20 meters in t seconds $t=\sqrt{\frac{2y}{g}}$ We plug in the known values to obtain: $t=\sqrt{\frac{2(20)}{9.8}}=2.0s$ The distance traveled by student is $x=vt$ We plug in the known values to obtain: $x=(2)(2.0)=4.0m$