Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 2 - Exercises and Problems: 84

Answer

Please see the work below.

Work Step by Step

We know that $t=\sqrt{\frac{2h}{g}}$ $t=\sqrt{\frac{2(0.196)}{9.8}}=0.2s$ As there are four drops at 0.2 seconds, the number of drops per second can be determined as $N=\frac{4}{0.2}=20 drops$
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