Answer
Please see the work below.
Work Step by Step
We know that the length of the window is given as
$d=vt-\frac{1}{2}gt^2$
We plug in the known values to obtain:
$-1.3=v(0.22)-\frac{1}{2}(9.8)(0.22)^2$
$v=-4.831\frac{m}{s}$
Hence the height above the window is:
$h=\frac{v^2}{2g}$
We plug in the known values to obtain:
$h=\frac{(4.831)^2}{2(9.8)}$
$h=1.2m$
