Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Exercises and Problems - Page 314: 53


4.88 degrees Celsius

Work Step by Step

We first find Q: $Q = mc\Delta T = (.05)(4.184)(T) = .21 T$ We set this equal to the value of Q for the other process to find: $ 1.025 = .21 T \\ T =4.88^{\circ}C$
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