Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Exercises and Problems - Page 314: 61


Please see the work below.

Work Step by Step

We know that $\Delta r=r\alpha \Delta T$ We plug in the known values to obtain: $0.1\times 10^{-6}m=0.5cm\times \Delta T(3.2)\times 10^{-6}-12\times 10^{-6}$ $\Delta T=\frac{-10^{-6}}{0.5\times 10^{-2}\times 8.8\times 10^{-6}}=-23K$ Now $\Delta T=T_f-T_i=-23K$ $\implies T_f=T_i-23K$ $T_f=330K-23K=307K$
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