Answer
Please see the work below.
Work Step by Step
(a) We know that
$mass \space of\space ice=\rho V$
We plug in the know values to obtain:
$m=917\times 10^{11}$
$m=9.17\times 10^{13}Kg$
Now $Energy \space converted\space to \space melt \space ice=mL_f$
We plug in the known values to obtain:
$Energy \space converted\space to \space melt \space ice=9.17\times 10^{13}\times 334=3.265\times 10^{16}KJ$
(b) As We know that
$P=\frac{Q}{t}$
We plug in the known values to obtain:
$P=\frac{3.265\times 10^{16}}{3weeks\times \frac{7days}{week}\times \frac{24hrs}{day}\times\frac{3600}{1hr}}$
$P=1.8\times 10^{10}KW$
